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Wednesday 5 June 2024

Physics Class 8th CH01: Pressure || By Pratap Sanjay Sir

Pressure Notes with Numerical Questions by Pratap Sanjay Sir

Pressure Notes with Numerical Questions

Pressure

Definition of Pressure

Pressure is the force exerted per unit area on the surface of an object.
It is a scalar quantity, meaning it only has magnitude and no direction.

Formula: Pressure (P) = Force (F) / Area (A)

P = F / A

Where:

  • P is the pressure
  • F is the force applied
  • A is the area over which the force is applied

SI Unit: Pascal (Pa) where 1 Pascal = 1 Newton per square meter (N/m²).

Understanding Pressure

  • If the same force is applied over a smaller area, the pressure increases.
  • If the same force is applied over a larger area, the pressure decreases.

Examples of Pressure in Daily Life

Example 1: A sharp knife cuts better because it exerts more pressure on the object due to its smaller area of contact.

Example 2: Snowshoes have a large surface area to distribute the weight of a person over a larger area, reducing pressure and preventing sinking into the snow.

Types of Pressure

Atmospheric Pressure: The pressure exerted by the weight of the atmosphere above us. Standard atmospheric pressure at sea level is approximately 101,325 Pa or 1 atmosphere (atm). Applications: Weather forecasting, altimeters in aircraft.

Liquid Pressure: Pressure exerted by a liquid in all directions due to its weight. Depends on the height (depth) and density of the liquid.

Formula: P = h * ρ * g

Applications of Pressure

Hydraulic Systems: Use liquid pressure to transmit force. Examples: Car brakes, hydraulic lifts.

Barometers and Manometers: Devices used to measure atmospheric and liquid pressures, respectively.

Important Concepts

Pascal’s Law: States that pressure applied to a confined fluid is transmitted equally in all directions. Basis for hydraulic systems.

Buoyant Force and Archimedes’ Principle: Buoyant force is the upward force exerted by a fluid on an object placed in it. Archimedes’ Principle: The buoyant force is equal to the weight of the fluid displaced by the object.

Numerical Problems

Problem 1

A girl applies a force of 12 N on an area of 10 cm2. What will be the pressure by her?

Solution:

Given:

  • Force (F) = 12 N
  • Area (A) = 10 cm2 = 10 x 10-4 m2 = 0.001 m2

Pressure (P) is given by:

P = F / A

P = 12 N / 0.001 m2 = 12000 Pa

Problem 2

Calculate the pressure exerted by a metallic block, which applies a force of 3 N, when it is placed on sand, (a) upright (b) on base. The dimensions of the metallic block are length 25 cm, height 10 cm, and width 5 cm.

(a) Upright

Solution:

Given:

  • Force (F) = 3 N
  • Length = 25 cm = 0.25 m
  • Height = 10 cm = 0.10 m
  • Width = 5 cm = 0.05 m

(a) When the block is upright:

  • Area (A) = Width x Height = 0.05 m x 0.10 m = 0.005 m2

Pressure (P) is given by:

P = F / A

P = 3 N / 0.005 m2 = 600 Pa

(b) On base

Solution:

(b) When the block is on its base:

  • Area (A) = Length x Width = 0.25 m x 0.05 m = 0.0125 m2

Pressure (P) is given by:

P = F / A

P = 3 N / 0.0125 m2 = 240 Pa

Problem 3

Calculate the pressure exerted on the floor by a boy standing on both feet if the weight of the boy is 40 kg. The area of contact of each shoe is 25 cm by 6 cm. (Take 1 kgwt = 10 N)

Solution:

Given:

  • Weight (Force) of the boy (F) = 40 kg x 10 N/kg = 400 N
  • Area of contact of each shoe = 25 cm x 6 cm = 150 cm2 = 150 x 10-4 m2 = 0.015 m2
  • Total area of contact (both shoes) = 2 x 0.015 m2 = 0.03 m2

Pressure (P) is given by:

P = F / A

P = 400 N / 0.03 m2 = 13333.33 Pa

Problem 4

A force of 200 N produces a pressure of 10000 Pa. Calculate the area of the surface on which the force acts.

Solution:

Given:

  • Force (F) = 200 N
  • Pressure (P) = 10000 Pa

Area (A) is given by:

A = F / P

A = 200 N / 10000 Pa = 0.02 m2

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